...]/; var strre = ; for (var i = 0; i < str.length; i++) { if (icount < len - 1) { temp = str.substr(i, 1); if (patrn.exec(temp) == null) { ico...
...ime || 1000; var j = {} for (var attr in json) { j[attr] = {}; if (attr == opacity) { j[attr].b = Math.round(css(obj, attr) * 100); } else { j[attr].b = parseInt(...
...d : wordDict) { int j = i - word.length(); if(j >= 0 && dp[j] && s.substring(j, i).equals(word)) { dp[i] = true; break; ...
... #includeusing namespace std;int main(){ int a,b; while(cin>>a>>b){ cout if(s[i]>=0&&s[i]=a&&s[i]=A&&s[i]=3;}int main(){ char s[20]; while(~scanf(%s,s)){ if(check(s)==1) puts(YES); else puts(NO...
... 500; while(divisor){ str += D; divisor--; } if(remainder >= 400){ str += CD; remainder -= 400; } // C,100 divisor = Math.floor(remainder / 1...
...reIpAddresses(String s) { ArrayList res = new ArrayList(); if (s.length() < 4 || s.length() > 12) { return res; } dfs(s,, res, 0); return res; ...
...sion tree of this expression, return the root of this expression tree. Clarification See wiki:Expression Tree Example For the expression (2*6-(23+7)/(1+2)) (which can be represented by [2 * 6 - ( 2...
...t-2) + b; }, easeInOut: function(t, b, c, d) { if ((t /= d / 2) < 1) return c / 2 * t * t + b; return -c / 2 * ((--t) * (t-2) - 1) + b; } }, ...
...tElementById(SomeElementYouWantToAnimate); function step(timestamp) { if (start === null) start = timestamp; var progress = timestamp - start; d.style.left = Math.min(progress/10, 200) + px;...
...tElementById(SomeElementYouWantToAnimate); function step(timestamp) { if (start === null) start = timestamp; var progress = timestamp - start; d.style.left = Math.min(progress/10, 200) + px;...
...tElementById(SomeElementYouWantToAnimate); function step(timestamp) { if (start === null) start = timestamp; var progress = timestamp - start; d.style.left = Math.min(progress/10, 200) + px;...
...tElementById(SomeElementYouWantToAnimate); function step(timestamp) { if (start === null) start = timestamp; var progress = timestamp - start; d.style.left = Math.min(progress/10, 200) + px;...
ChatGPT和Sora等AI大模型應用,將AI大模型和算力需求的熱度不斷帶上新的臺階。哪里可以獲得...
大模型的訓練用4090是不合適的,但推理(inference/serving)用4090不能說合適,...
圖示為GPU性能排行榜,我們可以看到所有GPU的原始相關性能圖表。同時根據訓練、推理能力由高到低做了...