Coins in a Line I Solution 第一個游戲者永遠拿不到第3n枚硬幣,所以在硬幣總數不能被3整除的情況下,都可以贏。 public class Solution { public boolean firstWillWin(int n) { return n % 3 != 0; } } Coins in a Line II Problem Th...
...所在區間以下從Redis獲取hash數據集,定位數據元素所在$coins_config對應的區間 ps:對于+=運算等,數組必須初始化,不然會報錯。 //登錄金幣 $coins_cofig = [0,3500,20000,30000,60000,100000,250000,500000,1000000,2500000]; $len = count($coins_cofig); //初始......
Coin ChangeYou are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amoun...
...與輸出應該規定如下。 /** * Count number of * @param {Array} coins array contains coins with different values * @param {Array} counts array contains corresponding counts of different coins * @returns {Nu...
題目要求 You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of m...
LintCode Coins in a line III There are n coins in a line. Two players take turns to take a coin from one of the ends of the line until there are no more coins left. The player with the larger amount ...
...繼續使用。 代碼如下: /** * Count number of * @param {Array} coins array contains coins with different values * @param {Array} counts array contains corresponding counts of different coins * @returns {N...
Problem You have a total of n coins that you want to form in a staircase shape, where every k-th row must have exactly k coins. Given n, find the total number of full staircase rows that can be formed...
題目要求 You have a total of n coins that you want to form in a staircase shape, where every k-th row must have exactly k coins. Given n, find the total number of full staircase rows that can be formed. ...
...為局部,跳躍位置作為局部 class Solution(object): def maxCoins(self, nums): :type nums: List[int] :rtype: int assert isinstance(nums,list) nums.insert(0,1)...
Problem You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount o...
LintCode: coins in a line I 有 n 個硬幣排成一條線。兩個參賽者輪流從右邊依次拿走 1 或 2 個硬幣,直到沒有硬幣為止。拿到最后一枚硬幣的人獲勝。 請判定 第一個玩家 是輸還是贏? n = 1, 返回 true.n = 2, 返回 true.n = 3, 返回 false.n...
LintCode Coins in a line II 有 n 個不同價值的硬幣排成一條線。兩個參賽者輪流從左邊依次拿走 1 或 2 個硬幣,直到沒有硬幣為止。計算兩個人分別拿到的硬幣總價值,價值高的人獲勝。 請判定 第一個玩家 是輸還是贏? 樣例給...
function MinCoinChange(coins) { var coins = coins; // cache存儲了1到37的最優解 // 37的找零 是36 或者32 或者27 或者12 的最優解個數+1 var cache = {}; this.makeChange = function(amount) { var me = this; if ...
...1個10美分和1個便士( 1美分) class MinCoinChange { constructor(coins) { this.coins = coins this.cache = {} } makeChange(amount) { if (!amount) return [] if (this.cache[amount]) return this.c...
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