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  • 二叉搜索樹的python實(shí)現(xiàn)

    ...有右子節(jié)點(diǎn)(r_child),找到右子節(jié)點(diǎn)下,最小的節(jié)點(diǎn)(r_child_smallest_child),將該節(jié)點(diǎn)與要?jiǎng)h除的節(jié)點(diǎn)換位置。具體操作為:先拿到r_child_smallest_child,再將該節(jié)點(diǎn)從以r_child為根的子樹中刪除。再將node_to_delete的左孩子作為r_child_smallest_...

    shixinzhang 評(píng)論0 收藏0
  • 【算法】算法圖解筆記_選擇排序

    ...快。需要的總時(shí)間為 O(n × n),即O(n2)。 Python版本: def findSmallest(arr): smallest = arr[0] smallest_index = 0 for i in range(1, len(arr)): if arr[i] < smallest: smallest = arr[i] smallest_...

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  • [Leetcode-Tree] Kth Smallest Element in a BST

    Kth Smallest Element in a BSTGiven a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BSTs total elements. Follo...

    Carl 評(píng)論0 收藏0
  • [LeetCode] 378. Kth Smallest Element in a Sorted M

    ...e each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix. Note that it is the kth smallest element in the sorted order, not the kth distinct element...

    Shihira 評(píng)論0 收藏0
  • [Leetcode] Kth Smallest Element in a BST 二叉搜索樹第k小節(jié)

    Kth Smallest Element in a BST Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note: You may assume k is always valid, 1 ≤ k ≤ BSTs total elements. Fo...

    Dean 評(píng)論0 收藏0
  • 八大排序算法使用python實(shí)現(xiàn)

    ...素均排序完畢。 以上節(jié)選自維基百科 代碼實(shí)現(xiàn): def findSmallest(arr): # 用于查找出數(shù)組中最小的元素,返回最小元素的索引。 smallest = arr[0] smallest_index = 0 for i in range(1, len(arr)): if smallest > arr[i]: sm...

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  • leetcode378. Kth Smallest Element in a Sorted Matr

    ...e each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix. Note that it is the kth smallest element in the sorted order, not the kth distinct elemen...

    dailybird 評(píng)論0 收藏0
  • Leetcode PHP題解--D18 908. Smallest Range I

    908. Smallest Range I 題目鏈接 908. Smallest Range I 題目分析 給定一個(gè)數(shù)組A和一個(gè)數(shù)字K,找到一個(gè)在-K和K之間的數(shù)字x并加到數(shù)組A中的每一個(gè)元素生成數(shù)組B,返回?cái)?shù)組B中最大值和最小值之差最小的值。 思路 根據(jù)題目,需要我們可...

    ethernet 評(píng)論0 收藏0
  • 378. Kth Smallest Element in a Sorted Matrix

    ...e each of the rows and columns are sorted in ascending order, find the kth smallest element in the matrix.Note that it is the kth smallest element in the sorted order, not the kth distinct element....

    makeFoxPlay 評(píng)論0 收藏0
  • 378. Kth Smallest Element in a Sorted Matrix

    378. Kth Smallest Element in a Sorted Matrix 題目鏈接:https://leetcode.com/problems... 求矩陣?yán)锩娴趉小的數(shù),首先比較容易想到的是用heap來(lái)做,maxheap或者minheap都可以,用maxheap的話把全部元素放進(jìn)heap里面,同時(shí)如果heap的size大于k就彈出,...

    Y3G 評(píng)論0 收藏0
  • [LintCode] Kth Smallest Number in Sorted Matrix

    Problem Find the kth smallest number in at row and column sorted matrix. Example Given k = 4 and a matrix: [ [1 ,5 ,7], [3 ,7 ,8], [4 ,8 ,9], ] return 5 Challenge O(k log n), n is the maximal n...

    mgckid 評(píng)論0 收藏0
  • [LintCode] The Smallest Difference

    ...etween A[i] and B[j] (|A[i] - B[j]|) is as small as possible, return their smallest difference. Example For example, given array A = [3,6,7,4], B = [2,8,9,3], return 0 Note 先對(duì)A,B排序,然后分別賦指針p1,p2。以兩個(gè)...

    Scorpion 評(píng)論0 收藏0
  • 483. Smallest Good Base

    483. Smallest Good Base 題目鏈接:https://leetcode.com/problems... enumerate,但是不是結(jié)果,而是冪。方法特別巧妙,另外求冪的和還可以優(yōu)化用快速冪來(lái)求。知道冪之后,根據(jù)逼近法,可以得到base:k = logm(n) = (long) (pow(n, 1/m)) = (long) (log(...

    mikasa 評(píng)論0 收藏0
  • leetcode373. Find K Pairs with Smallest Sums

    ...om the second array. Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) with the smallest sums. 兩個(gè)單調(diào)遞增的整數(shù)數(shù)組,現(xiàn)分別從數(shù)組1和數(shù)組2中取一個(gè)數(shù)字構(gòu)成數(shù)對(duì),求找到k個(gè)和最小的數(shù)對(duì)。 思路 這題采用最大堆作為輔助的數(shù)據(jù)結(jié)構(gòu)能夠完美的解決...

    Lavender 評(píng)論0 收藏0
  • Kth Smallest Element in a BST

    Kth Smallest Element in a BST 題目鏈接:https://leetcode.com/problems... inorder traverse: public class Solution { public int kthSmallest(TreeNode root, int k) { // morris: inorder traverse ...

    Barry_Ng 評(píng)論0 收藏0

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