...集合中添加新元素,如果該元素已存在則不做任何改變 s1 = {1,2,3} s1.add(qwe) print(s1) ---------- {1, 2, 3, qwe} update(*others)可將其他可迭代對象(比如字符串、列表、元組)添加到集合中,自動刪除重復元素 s1 = {1,2,3} it = [3,4,5] s1.update...
集合,不可重復的列表,可變類型 difference s1中存在,s2中不存在 s1 = {xmzncc,fcc} s2 = {alex,wusir} v = s1.difference(s2) print(v) s2中存在,s1中不存在 s1 = {xmzncc,fcc,test} s2 = {alex,wusir,xmzncc} v = s2.difference(s1) print(v) d...
... class TestString { 2 public static void main(String[] args) { 3 String s1 = Monday; 4 String s2 = Monday; 5 if (s1 == s2) 6 { 7 System.out.println(s1 == s2);} 8 else{ 9 System.out.println...
...合中的元素不可重復,這就類似于dict鍵。 創建集合 >>> s1 = set(qiswri) #有兩個i >>> s1 set([q, i, s, r, w]) #只有一個i >>> >>> s2 = set([123,google,facebook,book,facebook]); >>> s2 set([facebook, 123, google, book]) #只有一個faceb...
...blic class A { public static void main(String args[]) { String s1 = Hello; String s2 = Hello; System.out.println(s1 == s2); } } 肯定很多人說,輸出true,確實是輸出true,s1和s2引用的是同...
... public class TestString { public static void main(String[] args) { String s1 = Monday; String s2 = Monday; } } 上面這段程序中,到底有幾個對象呢? 來檢測一下吧,稍微改動一下程序 public class TestString { public stati...
...方法 5_String類的常見面試題* 1.判斷定義為String類型的s1和s2是否相等 String s1 = abc; String s2 = abc; System.out.println(s1 == s2); //true 兩個常量指向同一個地址值 System.out.println(s1.equals(s2)); //true 2.下面這句話在內存中創建...
...nitialize your data structure here. */ var MinStack = function() { this.s1 = []; this.s2 = []; }; /** * @param {number} x * @return {void} */ MinStack.prototype.push = function(x) { let...
... void main(String[] args) throws InterruptedException { String s1 = new String(vv); String s2 = vv; System.out.println(s1 == s2);//false } } 然后用...
...起組成新的集合并返回。它不改變原來的集合。 In [51]: s1, s2, s3 = {1,2,3}, {4,5,6}, {6,7,8} In [52]: s1.union(s2) Out[52]: {1, 2, 3, 4, 5, 6} In [53]: s1 Out[53]: {1, 2, 3} In [54]: s1.union(s2, s3) Out[54]: {1, 2, 3...
Problem Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = great: great / gr ...
...的; s={1,1,2,3,4,2,2} print(s) {1, 2, 3, 4} 如何定義一個空集合? s1 = {} # 默認情況是dict, 稱為字典 print(s1,type(s1)) {} 定義一個空集合 s2 = set([]) print(s2,type(s2)) set() 集合應用 列表去重 lee =[1,1,23,45,565,4,32,12,23,1] ...
...Person() // 子類型的原型為父類型的一個實例對象 var s1 = new Student(15000) var s2 = new Student(14000) console.log(s1,s2) 但這種方式實現的本質是通過將子類的原型指向了父類的實例,所以子類的實例就可以通過__proto__訪問到 S...
ChatGPT和Sora等AI大模型應用,將AI大模型和算力需求的熱度不斷帶上新的臺階。哪里可以獲得...
大模型的訓練用4090是不合適的,但推理(inference/serving)用4090不能說合適,...
圖示為GPU性能排行榜,我們可以看到所有GPU的原始相關性能圖表。同時根據訓練、推理能力由高到低做了...