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  • leetcode198,213 house robber

    House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...

    whidy 評論0 收藏0
  • [LeetCode] House Robber I II

    House Robber I Problem You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them...

    qpal 評論0 收藏0
  • [Leetcode] House Robber 打家劫舍

    House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...

    golden_hamster 評論0 收藏0
  • leetcode 198 House Robber

    題目詳情 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent ...

    jzman 評論0 收藏0
  • [LintCode/LeetCode] House Robber II

    ... tonight without alerting the police. Notice This is an extension of House Robber. Example nums = [3,6,4], return 6 Note 因為取了隊首就不能取隊尾,所以對dp數組循環兩次,一個從0取到len-2,一個從1取到len-1,比較兩次循環后隊尾元素,取較大者。注意,...

    OnlyLing 評論0 收藏0
  • LeetCode[337] House Robber III

    LeetCode[337] House Robber III The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only ...

    Dr_Noooo 評論0 收藏0
  • [LintCode/LeetCode] House Robber III

    ...來進行劃分的。 Solution public class Solution { public int houseRobber3(TreeNode root) { int[] A = dfs(root); return Math.max(A[0], A[1]); } public int[] dfs(TreeNode root) { ...

    macg0406 評論0 收藏0
  • leetcode337. House Robber III

    題目要求 The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. After a t...

    AlphaWallet 評論0 收藏0
  • LeetCode 337. House Robber III

    Description The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. Af...

    ymyang 評論0 收藏0
  • leetcode 部分解答索引(持續更新~)

    ...tock 167 Two Sum II - Input array is sorted 169 Majority Element 198 House Robber(03-25更新) 217 Contains Duplicate 219 Contains Duplicate II 268 Missing Number 283 Move Zeroes 414 Third Maximum Num...

    leo108 評論0 收藏0
  • LeetCode 攻略 - 2019 年 7 月上半月匯總(55 題攻略)

    ... 191 - 位1的個數(number-of-1-bits) ? 198 - 打家劫舍(house-robber) ? 202 - 快樂數(happy-number) ? 203 - 移除鏈表元素(remove-linked-list-elements) ? 204 - 計數質數(count-primes) ? 205 - 同構字符串(isomorphic-strings) ? 206 - ...

    warmcheng 評論0 收藏0
  • react-native, react-navigation, redux 學習筆記

    ...spatch(addmoney(earn.money + 1000000)) return dispatch(setLastJob(robber)) } } // 定義一個賺錢的方式2,建材轉移者 export function moveBrick(){ return (dispatch, getState) => { console.log(...

    妤鋒シ 評論0 收藏0
  • 前端 | 每天一個 LeetCode

    ...ts ↗ Easy 202 快樂數 Happy Number ↗ Easy 198 打家劫舍 House Robber ↗ Easy 191 位 1 的個數 Number of 1 Bits ↗ Easy 190 顛倒二進制位 Reverse Bits ↗ Easy 189 旋轉數組 Rotate Array ↗ Easy 172 階乘后的零 Factorial Tr...

    張漢慶 評論0 收藏0
  • LeetCode 攻略 - 2019 年 7 月下半月匯總(100 題攻略)

    ... 191 - 位1的個數(number-of-1-bits) ? 198 - 打家劫舍(house-robber) ? 202 - 快樂數(happy-number) ? 203 - 移除鏈表元素(remove-linked-list-elements) ? 204 - 計數質數(count-primes) ? 205 - 同構字符串(isomorphic-strings) ? 206 - ...

    tain335 評論0 收藏0
  • LeetCode 精選TOP面試題【51 ~ 100】

    ...)+動規) [198. 打家劫舍](https://leetcode-cn.com/problems/house-robber/)(動規) [136. 只出現一次的數字](https://leetcode-cn.com/problems/single-number/)(異或運算) [69. Sqrt(x)](https://leetcode-cn.com/problems/sqr...

    Clect 評論0 收藏0

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