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  • leetcode410. Split Array Largest Sum

    ...gers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note: If n is the length of array, ass...

    Jonathan Shieber 評論0 收藏0
  • [LeetCode] 689. Maximum Sum of 3 Non-Overlapping S

    ...lem In a given array nums of positive integers, find three non-overlapping subarrays with maximum sum. Each subarray will be of size k, and we want to maximize the sum of all 3*k entries. Return th...

    dailybird 評論0 收藏0
  • 幾種常見排序算法

    ...es. Abstract in-place merge(原地歸并的抽象方法) Given two sorted subarrays a[lo] to a[mid] and a[mid+1] to a[hi],replace with sorted subarray a[lo] to a[hi] 步驟: 先將所有元素復(fù)制到aux[]中,再歸并回a[]中。 歸并時(shí)的四個(gè)判斷: 左半邊用盡...

    ChristmasBoy 評論0 收藏0
  • Java - Sorting Algorithms

    ...t involves the following three steps: Divide the array into two (or more) subarrays. Sort each subarray (Conquer). Merge them into one. Implement Mergesort in Java using Arrays public class Merg...

    陳江龍 評論0 收藏0
  • [LeetCode] 560. Subarray Sum Equals K

    ...integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k. Example 1: Input:nums = [1,1,1], k = 2 Output: 2 Note:The length of the array is in range...

    ccj659 評論0 收藏0
  • [LeetCode] 548. Split Array with Equal Sum

    ... satisfies following conditions: 0 < i, i + 1 < j, j + 1 < k < n - 1Sum of subarrays (0, i - 1), (i + 1, j - 1), (j + 1, k - 1) and (k + 1, n - 1) should be equal.where we define that subarray (L, ...

    frank_fun 評論0 收藏0
  • 數(shù)據(jù)結(jié)構(gòu)與算法——常用排序算法及其Java實(shí)現(xiàn)

    ... int hi) { // precondition: a[lo .. mid] and a[mid+1 .. hi] are sorted subarrays assert isSorted(a, lo, mid); assert isSorted(a, mid+1, hi); // copy to aux[] for (int k = lo; k...

    eternalshallow 評論0 收藏0

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