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面向?qū)ο?--構(gòu)造函數(shù)

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摘要:面向?qū)ο笠粍?chuàng)建對(duì)象構(gòu)造函數(shù)或?qū)ο笞置媪縿?chuàng)建單個(gè)對(duì)象工廠(chǎng)模式用函數(shù)來(lái)封裝特定接口創(chuàng)建對(duì)象的細(xì)節(jié)構(gòu)造函數(shù)原型模式組合模式最常用動(dòng)態(tài)原型模式寄生構(gòu)造函數(shù)模式工廠(chǎng)模式缺點(diǎn)函數(shù)能夠創(chuàng)建根據(jù)接受的參數(shù)來(lái)構(gòu)建一個(gè)包含所有必要信息的對(duì)象。




    
    面向?qū)ο?/title>
</head>
<body>
    一:創(chuàng)建對(duì)象
        1.Object構(gòu)造函數(shù)或?qū)ο笞置媪縿?chuàng)建單個(gè)對(duì)象
        2.工廠(chǎng)模式:(用函數(shù)來(lái)封裝特定接口創(chuàng)建對(duì)象的細(xì)節(jié))
        3.構(gòu)造函數(shù):
        4.原型模式:
        5.組合模式(最常用*)
        6.動(dòng)態(tài)原型模式
        7.寄生構(gòu)造函數(shù)模式

</body>
<script type="text/javascript">
    // 工廠(chǎng)模式
    function createPerson(name,age,job) {
        var o = new Object();
        o.name = name;
        o.age = age;
        o.job = job;
        o.sayName = function(){
            alert(this.name);
        }
        return o;
    }
    var person1 = createPerson("leo",29,"doctor");
    var person2 = createPerson("jack",28,"teacher");
    // 缺點(diǎn):函數(shù)createPerson()能夠創(chuàng)建根據(jù)接受的參數(shù)來(lái)構(gòu)建一個(gè)包含所有必要信息的     Person對(duì)象。
   //可以無(wú)數(shù)次的調(diào)用這個(gè)函數(shù),而每次他都會(huì)返回三個(gè)屬性和一個(gè)方法的對(duì)象。
   //工廠(chǎng)模式雖然解決了創(chuàng)建多個(gè)相同對(duì)象的問(wèn)題,但卻沒(méi)有解決對(duì)象識(shí)別的問(wèn)題!!!(不懂什么意思)


    // 構(gòu)造函數(shù)模式
    function Person(name,age,job){
        this.name = name;
        this.age = age;
        this.job = job;
        this.sayName = function(){
            alert(this.name);
        }
    }
    var person1 = new Person("leo",29,"doctor");
    var person2 = new Person("jack",28,"teacher");
    // 優(yōu)點(diǎn):創(chuàng)建自定義構(gòu)造函數(shù)意味著將來(lái)我們可以將他的實(shí)例標(biāo)識(shí)為一種特定的類(lèi)型,
    //而這正是構(gòu)造函數(shù)模式勝過(guò)工廠(chǎng)模式的地方
    // 缺點(diǎn):就是每個(gè)方法都要在每個(gè)實(shí)例上創(chuàng)建一遍,在前面的例子中person1,person2都有一個(gè)同樣的sayName方法,等于創(chuàng)建了兩次相同的sayName方法

    
    //原型模式
    function Person(){

    }
    Person.prototype.name = "leo";
    Person.prototype.age = 29;
    Person.prototype.job = "doctor";
    Person.prototype.sayName = function(){
        alert(this.name);
    }
    var person1 = new Person();
    person1.sayName();  // leo
    var person2 = new Person();
    person2.sayName();  //  leo
    alert(person1.sayName == person2.sayName);  //true 
    // 優(yōu)點(diǎn):可以讓所有的對(duì)象實(shí)例共享它所包含的所有屬性和方法,
    //換句話(huà)說(shuō)不必在構(gòu)造函數(shù)中定義對(duì)象實(shí)例的信息,而是可以將這些信息直接添加到原型對(duì)象中
    // 缺點(diǎn):省略掉了為構(gòu)造函數(shù)傳遞初始化參數(shù)的步驟,使得所有實(shí)例在默認(rèn)情況下都取得相同的屬性值
          // 屬性共享

    // 組合模式  
    // 使用構(gòu)造函數(shù)模式和原型模式,構(gòu)造函數(shù)定義實(shí)例屬性,原型定義方法和共享屬性
    function Person(name,age,job){
        this.name = name;
        this.age = age;
        this.job = job;
    }
    Person.prototype = {
        constructor:Person,  // 對(duì)象字面量形式會(huì)使constructor屬性重寫(xiě),所以要重新賦值
        sayName:function(){
            alert(this.name);
        }
    }

</script>
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                                  <li id="vlfh7p5"    class="ellipsis"><a class="hpf" href="http://specialneedsforspecialkids.com/yun/81180.html">上一篇:面向?qū)ο?非構(gòu)造函數(shù)的繼承</a></li>  
                                                
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title: JS對(duì)象(1)重新認(rèn)識(shí)面向?qū)ο? date: 2016-10-05      tags: JavaScript

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Java知識(shí)點(diǎn)總結(jié)(面向?qū)ο螅?@(Java知識(shí)點(diǎn)總結(jié))[Java, Java面向?qū)ο骫
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面向?qū)ο蟾拍?是相對(duì)于面向過(guò)程而言,過(guò)程其實(shí)就是函數(shù),對(duì)象是將函數(shù)和屬性進(jìn)行了封...</p>
                                                   
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