国产xxxx99真实实拍_久久不雅视频_高清韩国a级特黄毛片_嗯老师别我我受不了了小说

資訊專欄INFORMATION COLUMN

[LeetCode] 71. Simplify Path

superw / 2839人閱讀

Problem

Given an absolute path for a file (Unix-style), simplify it.

For example,

path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
path = "/a/../../b/../c//.//", => "/c"        //here: b is cancelled out, a is cancelled out
path = "/a//b////c/d//././/..", => "/a/b/c"   //here d is cancelled out

In a UNIX-style file system, a period (".") refers to the current directory, so it can be ignored in a simplified path. Additionally, a double period ("..") moves up a directory, so it cancels out whatever the last directory was. For more information, look here: https://en.wikipedia.org/wiki...

Corner Cases:

Did you consider the case where path = "/../"?
In this case, you should return "/".
Another corner case is the path might contain multiple slashes "/" together, such as "/home//foo/".
In this case, you should ignore redundant slashes and return "/home/foo".

Solution 
class Solution {
    public String simplifyPath(String path) {
        Deque stack = new ArrayDeque<>();
        Set ignore = new HashSet<>(Arrays.asList("", ".", ".."));
        for (String dir: path.split("/")) {
            if (!stack.isEmpty() && dir.equals("..")) stack.pop();
            if (!ignore.contains(dir)) stack.push(dir);
        }
        String res = "";
        while (!stack.isEmpty()) {
            res = "/"+stack.pop()+res;
        }
        if (res.equals("")) return "/";
        return res;
    }
}

文章版權(quán)歸作者所有，未經(jīng)允許請勿轉(zhuǎn)載,若此文章存在違規(guī)行為，您可以聯(lián)系管理員刪除。

轉(zhuǎn)載請注明本文地址：http://specialneedsforspecialkids.com/yun/72713.html

相關(guān)文章

  • leetcode71. Simplify Path

    摘要：標(biāo)題文字簡化風(fēng)格的絕對路徑。我們可以首先將所有的內(nèi)容從中分離出來，然后分別處理。這里我們需要用到堆棧的數(shù)據(jù)結(jié)構(gòu)。堆棧有很多種實(shí)現(xiàn)方式，中的類類都可以實(shí)現(xiàn)其功能。我們將讀到的路徑入棧，根據(jù)操作符出棧，最后將棧中剩余的元素組織成路徑返回即可。 標(biāo)題文字 Given an absolute path for a file (Unix-style), simplify it. For exa...

    darkerXi 評論0 收藏0

  • 71. Simplify Path

    摘要：題目解答的規(guī)則如下三種需要跳過的情況當(dāng)遇到時，需要向前進(jìn)出來的順序是反的，所以加的時候，把最新出來的路徑加在前面 題目：Given an absolute path for a file (Unix-style), simplify it. For example,path = /home/, => /homepath = /a/./b/../../c/, => /cclick to ...

    EdwardUp 評論0 收藏0

  • [Leetcode] Simplify Path 化簡路徑

    摘要：棧法復(fù)雜度時間空間思路思路很簡單，先將整個路徑按照分開來，然后用一個棧，遇到時彈出一個，遇到和空字符串則不變，遇到正常路徑則壓入棧中。注意如果結(jié)果為空，要返回一個彈出棧時要先檢查棧是否為空代碼 Simplify Path Given an absolute path for a file (Unix-style), simplify it. For example, path = /...

    liangzai_cool 評論0 收藏0

  • 【Leetcode】71. 簡化路徑

    摘要：題目給定一個文檔的完全路徑，請進(jìn)行路徑簡化。例如，邊界情況你是否考慮了路徑的情況在這種情況下，你需返回。此外，路徑中也可能包含多個斜杠，如。文化和社會被恐懼所塑造，在將來這無疑也不會消失。 題目 給定一個文檔 (Unix-style) 的完全路徑，請進(jìn)行路徑簡化。 例如，path = /home/, => /homepath = /a/./b/../../c/, => /c 邊界情況:...

    liuchengxu 評論0 收藏0

  • 【Leetcode】71. 簡化路徑

    摘要：題目給定一個文檔的完全路徑，請進(jìn)行路徑簡化。例如，邊界情況你是否考慮了路徑的情況在這種情況下，你需返回。此外，路徑中也可能包含多個斜杠，如。文化和社會被恐懼所塑造，在將來這無疑也不會消失。 題目 給定一個文檔 (Unix-style) 的完全路徑，請進(jìn)行路徑簡化。 例如，path = /home/, => /homepath = /a/./b/../../c/, => /c 邊界情況:...

    afishhhhh 評論0 收藏0

發(fā)表評論

0條評論

最新活動
閱讀需要支付1元查看
<