Problem
Given a binary tree, return the zigzag level order traversal of its nodes" values. (ie, from left to right, then right to left for the next level and alternate between).
ExampleGiven binary tree {3,9,20,#,#,15,7},
3 / 9 20 / 15 7
return its zigzag level order traversal as:
[ [3], [20,9], [15,7] ]Note Solution
public class Solution { public ArrayList> zigzagLevelOrder(TreeNode root) { ArrayList > res = new ArrayList(); if (root == null) return res; boolean LR = true; Stack stack = new Stack(); stack.push(root); while (!stack.isEmpty()) { Stack curStack = new Stack(); ArrayList curList = new ArrayList(); while (!stack.isEmpty()) { TreeNode cur = stack.pop(); curList.add(cur.val); if (LR) { if (cur.left != null) curStack.push(cur.left); if (cur.right != null) curStack.push(cur.right); } else { if (cur.right != null) curStack.push(cur.right); if (cur.left != null) curStack.push(cur.left); } } stack = curStack; res.add(curList); LR = !LR; } return res; } }
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Problem Given a binary tree, return the level order traversal of its nodes values. (ie, from left to right, level by level). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / 9 20 / ...
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