摘要：刷題繼續上一期和大家分享了前道題，今天繼續來刷解法一解法二解法三解法一解法二解法三解法四解法一解法二解法三解法一解法二解法三解法一解法二解法一解法一解法二解法一解法二解法三解法四解法一解法一源代碼下載這十道題的

上一期和大家分享了前10道題，今天繼續來刷11~20

Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a comma separated sequence.
Example:

0100,0011,1010,1001

Then the output should be:

1010

Notes: Assume the data is input by console.

def check(x):                   # check function returns true if divisible by 5
    return int(x,2)%5 == 0      # int(x,b) takes x as string and b as base from which
                                # it will be converted to decimal
data = input().split(",")

data = list(filter(check,data)) # in filter(func,object) function, elements are picked from "data" if found True by "check" function
print(",".join(data))

value = []
items=[int(x) for x in input().split(",")]
result = " ".join(str(x) for x in items if x %5==0 )
print(",".join(result))

data = input().split(",")
data = list(filter(lambda i:int(i,2)%5==0,data))   
print(",".join(data))

Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number.The numbers obtained should be printed in a comma-separated sequence on a single line.

values = []
for i in range(1000, 3001):
    s = str(i)
    if (int(s[0])%2==0) and (int(s[1])%2==0) and (int(s[2])%2==0) and (int(s[3])%2==0):
        values.append(s)
print (",".join(values))

lst = []

for i in range(1000,3001):
    flag = 1
    for j in str(i):          # every integer number i is converted into string
        if ord(j)%2 != 0:     # ord returns ASCII value and j is every digit of i
            flag = 0          # flag becomes zero if any odd digit found
    if flag == 1:
        lst.append(str(i))    # i is stored in list as string

print(",".join(lst))  

def check(element):
    return all(ord(i)%2 == 0 for i in element)  # all returns True if all digits i is even in element

lst = [str(i) for i in range(1000,3001)]        # creates list of all given numbers with string data type
lst = list(filter(check,lst))                   # filter removes element from list if check condition fails
print(",".join(lst))

lst = [str(i) for i in range(1000,3001)]
lst = list(filter(lambda i:all(ord(j)%2 == 0 for j in i),lst ))   # using lambda to define function inside filter function
print(",".join(lst))

Write a program that accepts a sentence and calculate the number of letters and digits.
Suppose the following input is supplied to the program:

hello world! 123

Then, the output should be:

LETTERS 10
DIGITS 3

text_input = input()

d={"DIGITS":0, "LETTERS":0,"SPACE":0}
d["DIGITS"]= sum(c.isdigit() for c in text_input)
d["LETTERS"]= sum(c.isalpha() for c in text_input)
d["SPACE"]  = sum(c.isspace() for c in text_input)

for k,v in d.items():
    print(k,v)

word = input()
letter,digit = 0,0

for i in word:
    if ("a"<=i and i<="z") or ("A"<=i and i<="Z"):
        letter+=1
    if "0"<=i and i<="9":
        digit+=1

print("LETTERS {0}
DIGITS {1}".format(letter,digit))

word = input()
letter,digit = 0,0

for i in word:
    letter+=i.isalpha()         # returns True if alphabet
    digit+=i.isnumeric()        # returns True if numeric

print("LETTERS %d
DIGITS %d"%(letter,digit))       # two different types of formating method is shown in both solution

Write a program that accepts a sentence and calculate the number of upper case letters and lower case letters.
Suppose the following input is supplied to the program:

Hello world!

Then, the output should be:

UPPER CASE 1
LOWER CASE 9

word = input()
upper,lower = 0,0

for i in word:
    if "a"<=i and i<="z" :
        lower+=1
    if "A"<=i and i<="Z":
        upper+=1

print("UPPER CASE {0}
LOWER CASE {1}".format(upper,lower))

text_input = input()
d={"UPPER CASE":0, "LOWER CASE":0}
for c in text_input:
    if c.isupper():
        d["UPPER CASE"]+=1
    elif c.islower():
        d["LOWER CASE"]+=1
    else:
        pass
print ("UPPER CASE", d["UPPER CASE"])
print ("LOWER CASE", d["LOWER CASE"])

word = input()
upper = sum(1 for i in word if i.isupper())         
lower = sum(1 for i in word if i.islower())

print("UPPER CASE {0}
LOWER CASE {1}".format(upper,lower))

Write a program that computes the value of a+aa+aaa+aaaa with a given digit as the value of a.
Suppose the following input is supplied to the program:

9

Then, the output should be:

11106

a = input()
total,tmp = 0,str()        # initialing an integer and empty string

for i in range(4):
    tmp+=a               # concatenating "a" to "tmp"
    total+=int(tmp)      # converting string type to integer type

print(total)

a = input()
total = int(a) + int(2*a) + int(3*a) + int(4*a)  # N*a=Na, for example  a="23", 2*a="2323",3*a="232323"
print(total)

Use a list comprehension to square each odd number in a list. The list is input by a sequence of comma-separated numbers.
Suppose the following input is supplied to the program:

1,2,3,4,5,6,7,8,9

Then, the output should be:

1,3,5,7,9

values = input()
numbers = [x for x in values.split(",") if int(x)%2!=0]
print (",".join(numbers))

Write a program that computes the net amount of a bank account based a transaction log from console input. The transaction log format is shown as following:

D 100
W 200

D means deposit while W means withdrawal.

Suppose the following input is supplied to the program:

D 300
D 300
W 200
D 100

Then, the output should be:

500

netAmount = 0
while True:
    s = input()
    if not s:
        break
    values = s.split(" ")
    operation = values[0]
    amount = int(values[1])
    if operation=="D":
        netAmount+=amount
    elif operation=="W":
        netAmount-=amount
    else:
        pass
print(netAmount)

total = 0
while True:
    s = input().split()
    if not s:            # break if the string is empty
        break
    cm,num = map(str,s)  

    if cm=="D":
        total+=int(num)
    if cm=="W":
        total-=int(num)

print(total)

A website requires the users to input username and password to register. Write a program to check the validity of password input by users.
Following are the criteria for checking the password:

At least 1 letter between [a-z]

At least 1 number between [0-9]

At least 1 letter between [A-Z]

At least 1 character from [$#@]

Minimum length of transaction password: 6

Maximum length of transaction password: 12

Your program should accept a sequence of comma separated passwords and will check them according to the above criteria. Passwords that match the criteria are to be printed, each separated by a comma.
Example
If the following passwords are given as input to the program:

ABd1234@1,a F1#,2w3E*,2We3345

Then, the output of the program should be:

ABd1234@1

import re

value = []
items=[x for x in input().split(",")]
for p in items: 
    if (len(p)<6 or len(p)>12):
        break
    elif not re.search("[a-z]",p):
        break
    elif not re.search("[0-9]",p):
        break
    elif not re.search("[A-Z]",p):
        break
    elif not re.search("[$#@]",p):
        break
    elif re.search("s",p):
        break
    else:
        value.append(p)
        break

print (",".join(value))

def is_low(x):       # Returns True  if the string has a lowercase
    for i in x:
        if "a"<=i and i<="z":
            return True
    return  False

def is_up(x):       # Returns True  if the string has a uppercase
    for i in x:
        if "A"<= i and i<="Z":
            return True
    return  False

def is_num(x):          # Returns True  if the string has a numeric digit
    for i in x:
        if "0"<=i and i<="9":
            return True
    return  False

def is_other(x):       # Returns True if the string has any "$#@"
    for i in x:
        if i=="$" or i=="#" or i=="@":
            return True
    return False

s = input().split(",")            
lst = []

for i in s:
    length = len(i)
    if 6 <= length and length <= 12 and is_low(i) and is_up(i) and is_num(i) and is_other(i):   #Checks if all the requirments are fulfilled
        lst.append(i)

print(",".join(lst))

def check(x):
    cnt = (6<=len(x) and len(x)<=12)
    for i in x:
        if i.isupper():
            cnt+=1
            break
    for i in x:
        if i.islower():
            cnt+=1
            break
    for i in x:
        if i.isnumeric():
            cnt+=1
            break
    for i in x:
        if i=="@" or i=="#"or i=="$":
            cnt+=1
            break
    return cnt == 5               # counting if total 5 all conditions are fulfilled then returns True

s = input().split(",")
lst = filter(check,s)             # Filter function pick the words from s, those returns True by check() function
print(",".join(lst))

import  re

s = input().split(",")
lst = []

for i in s:
    cnt = 0
    cnt+=(6<=len(i) and len(i)<=12)
    cnt+=bool(re.search("[a-z]",i))      # here re module includes a function re.search() which returns the object information
    cnt+=bool(re.search("[A-Z]",i))      # of where the pattern string i is matched with any of the [a-z]/[A-z]/[0=9]/[@#$] characters
    cnt+=bool(re.search("[0-9]",i))      # if not a single match found then returns NONE which converts to False in boolean
    cnt+=bool(re.search("[@#$]",i))      # expression otherwise True if found any.
    if cnt == 5:
        lst.append(i)

print(",".join(lst))

You are required to write a program to sort the (name, age, score) tuples by ascending order where name is string, age and score are numbers. The tuples are input by console. The sort criteria is:

1: Sort based on name

2: Then sort based on age

3: Then sort by score

The priority is that name > age > score.
If the following tuples are given as input to the program:

Tom,19,80
John,20,90
Jony,17,91
Jony,17,93
Json,21,85

Then, the output of the program should be:

[("John", "20", "90"), ("Jony", "17", "91"), ("Jony", "17", "93"), ("Json", "21", "85"), ("Tom", "19", "80")]

lst = []
while True:
    s = input().split(",")
    if not s[0]:                          # breaks for blank input
        break
    lst.append(tuple(s))

lst.sort(key= lambda x:(x[0],x[1],x[2])) 
print(lst)

Define a class with a generator which can iterate the numbers, which are divisible by 7, between a given range 0 and n.

class Test:
    def generator(self,n):
        return [i for i in range(n) if i%7==0]   

n = int(input())
num = Test()
lst = num.generator(n)
print(lst)

這十道題的代碼在我的github上，如果大家想看一下每道題的輸出結果，可以點擊以下鏈接下載：

Python 11-20題

我的運行環境Python 3.6+,如果你用的是Python 2.7版本，絕大多數不同就體現在以下3點：

raw_input()在Python3中是input()

print需要加括號

fstring可以換成.format(),或者%s，%d

謝謝大家，我們下期見！希望各位朋友不要吝嗇，把每道題的更高效的解法寫在評論里，我們一起進步！！！